A user crontab contains the entry `0 6 1 * 1 /usr/local/bin/report`. On which days does the job actually run?

LPIC-1 Exam 102-500, objective 107. Administrative tasks hard

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The options

Correct On the first day of the month, and additionally on every Monday

Correct. When both the day-of-month and the day-of-week fields are restricted, cron treats them as alternatives: the command runs if either matches.

Not correct Only on the first day of the month, and only when that day is a Monday

Wrong. That is the intersection of the two fields. Cron uses the union, not the intersection, when neither field is an asterisk.

Not correct Only on the first Monday of each month

Wrong. Cron has no nth-weekday-of-month syntax; expressing that requires a daily job plus a date test inside the script.

Not correct Only on the first day of the month; the day-of-week field is ignored because a day-of-month was given

Wrong. Neither field is ignored here. A field drops out of the decision only when it is itself a lone asterisk: with `* * 1` cron runs on Mondays only, and with `1 * *` it runs on the 1st only. Because both fields are restricted in this entry, cron takes their union.

Why

The scheduling fields are minute, hour, day of month, month, day of week. Month, minute and hour are ANDed with everything else, but day of month and day of week are ORed whenever both are restricted. Because of this, `0 6 1 * 1` fires roughly five times as often as most people intend. Leave one of the two fields as * whenever you want a single, unambiguous rule.

Where this comes from

Cited
manual page crontab(5)

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Practise LPIC-1 Exam 102-500

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