A variable named PROJECT appears in the output of set, but not in the output of env, and a script started from that shell cannot see it. What is the state of PROJECT?

LPIC-1 Exam 102-500, objective 105. Shells and shell scripting medium

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The options

Correct It is a shell variable that has not been exported, so it is not part of the environment passed to child processes

Correct. set lists all shell variables; env lists only those marked for export. Being in one and not the other is the definition of an unexported shell variable.

Not correct It is set to an empty value, which env suppresses from its output

Wrong. env prints exported variables whose value is empty as NAME= with nothing after the equals sign. Emptiness is not why it is missing.

Not correct It is marked read-only, and env only prints writable variables

Wrong. readonly prevents reassignment and unsetting; it has no bearing on export status, and read-only exported variables appear in env normally.

Not correct It is a shell function rather than a variable, and functions never appear in env

Wrong. set does list functions as well as variables, but a function would be shown with its body and parentheses, and a function can in fact be put into the environment with export -f.

Why

Every variable in bash exists in the shell; only exported ones are copied into the environment that execve hands to a child process. set with no arguments prints all shell variables and functions of the current shell, while env and printenv show only the exported set. export PROJECT promotes an existing variable without changing its value, and export -n demotes it again.

Where this comes from

Cited
manual page bash(1)

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