An executable script contains only the line `export EDITOR=vim`. After running it as `./setenv.sh`, `echo $EDITOR` in the calling shell prints nothing. What explains this?

LPIC-1 Exam 102-500, objective 105. Shells and shell scripting medium

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The options

Not correct The script is missing execute permission, so the assignment never ran.

Wrong. Without execute permission the shell would refuse to run it and print a permission-denied error, not run it silently.

Not correct export only works for variables that already exist in the environment.

Wrong. `export NAME=value` creates the variable and marks it for export in one step. Existence beforehand is not required.

Not correct Environment variables must be assigned with set instead of export.

Wrong. `set` is a real builtin, but it toggles shell options and sets positional parameters. It does not create environment variables.

Correct Executing the script starts a child shell, and a child can never alter its parent's environment.

Correct. Exported variables propagate downward to children only. To change the current shell you must run the script with `source setenv.sh` or `. setenv.sh`, which executes its lines in the current shell.

Why

Executing a script forks a new process running a new shell. Anything that shell changes, including variables, the working directory and umask, dies with it. Sourcing (`.` or `source`) does not fork: the commands run in the current shell, so their side effects persist. This is exactly why ~/.bashrc is sourced rather than executed.

Where this comes from

Cited
LPI exam objective 105.1
What it says
Understand the difference between sourcing a file and executing it.

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