A nightly maintenance script prints progress on standard output and problems on standard error. Both streams should end up in the systemd journal under an identifier you can filter on later. Which invocation achieves that?
LPIC-1 Exam 102-500, objective 108. Essential system services medium
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How these questions are written — where each question comes from, what the verification ledger records, and what happens when one is found wrong.
The options
Correct systemd-cat -t maintenance /usr/local/sbin/maintenance.sh
Correct. systemd-cat executes the program with both of its output streams connected to the journal, and -t sets the syslog identifier the entries are tagged with.
Not correct logger -t maintenance /usr/local/sbin/maintenance.sh
Wrong. logger treats its non-option arguments as the message text, so this writes the literal string /usr/local/sbin/maintenance.sh into the log. The script is never executed.
Not correct journalctl -t maintenance /usr/local/sbin/maintenance.sh
Wrong direction. journalctl only reads the journal; -t filters existing entries by identifier. It has no way to run a program or to write an entry.
Not correct echo /usr/local/sbin/maintenance.sh | systemd-cat -t maintenance
Wrong. With no command to run, systemd-cat copies its own standard input into the journal, so the path is logged as one line and the script still does not run.
Why
systemd-cat has two modes: given a command it runs it with stdout and stderr redirected into the journal, and given none it forwards its own standard input. Either way -t sets SYSLOG_IDENTIFIER and -p the default priority, so the entries come back with `journalctl -t maintenance`. logger is the equivalent for writing a single message through the syslog interface, and it too takes -t and -p.
Where this comes from
- Cited
- manual page systemd-cat(1)
Practise this
Reading one question is not practice. The trainer will draw a short set from objective 108 and space the ones you get wrong.
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