A machine with no working time synchronisation is running four minutes fast, and you must correct the system clock by hand to 2026-03-01 09:00:00. Which command does that?

LPIC-1 Exam 102-500, objective 107. Administrative tasks medium

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The options

Correct date -s "2026-03-01 09:00:00"

Correct. -s (--set) sets the system clock to the time given, and requires the privileges to do so.

Not correct date -d "2026-03-01 09:00:00"

Wrong. -d parses the string and prints the resulting time. It is a calculator and formatter for arbitrary dates and never touches the clock.

Not correct date --utc "2026-03-01 09:00:00"

Wrong. --utc (-u) only asks that input and output be interpreted in UTC. It sets nothing, and a bare non-option argument here is not a valid format string.

Not correct hwclock --hctosys

Wrong direction, and wrong value. --hctosys copies the hardware clock into the system clock, so it would install whatever the RTC currently holds rather than the time you specified. --systohc is the reverse copy you would run afterwards.

Why

date -d and date -s look similar and do opposite things: one displays a computed time, the other installs it. The plus-prefixed argument is a third case again, a format string for output, as in `date +%Y-%m-%d`. After setting the system clock by hand, `hwclock --systohc` writes it through to the RTC so that the correction survives a reboot; on a systemd host `timedatectl set-time` performs both steps.

Where this comes from

Cited
manual page date(1)

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Practise LPIC-1 Exam 102-500

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