The file /etc/passwd has colon-separated fields. Type the complete command that prints only the third field (the UID) of every line, using cut and passing the file as an argument.
LPIC-1 Exam 101-500, objective 103. GNU and Unix commands medium
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Answer
Type the answer.
Accepted answers
cut -d: -f3 /etc/passwdcut -d: -f 3 /etc/passwdcut -d : -f3 /etc/passwdcut -d : -f 3 /etc/passwdcut -d ':' -f3 /etc/passwdcut -d ':' -f 3 /etc/passwdcut -d':' -f3 /etc/passwdcut -d':' -f 3 /etc/passwdcut -d ":" -f3 /etc/passwdcut -d":" -f3 /etc/passwdcut -f3 -d: /etc/passwdcut -f 3 -d: /etc/passwdcut --delimiter=: --fields=3 /etc/passwd
Case sensitive — Linux is, and grading LS as ls would teach a falsehood.
Why
cut -d sets the field delimiter and -f selects the fields; -f3 is one field, -f1,3 a list, -f1-3 a range. Without -d, cut assumes TAB, which is why cutting fields out of a space-aligned listing usually fails. -c selects character positions instead of fields.
Where this comes from
- Cited
- LPI exam objective 103.2
- What it says
- Extract fields from a delimited text stream with cut.
Practise this
Reading one question is not practice. The trainer will draw a short set from objective 103 and space the ones you get wrong.
More questions on this objective
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