A file contains one plain integer per line. Sorting it with plain `sort` produces the order 1, 10, 2, 20, 3. Which option makes sort order the numbers by value?
LPIC-1 Exam 101-500, objective 103. GNU and Unix commands medium
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The options
Not correct sort -f
Wrong. -f folds case, treating lowercase and uppercase as equal. Digits have no case, so the comparison stays lexical and the order does not change at all.
Correct sort -n
Correct. -n compares the leading numeric string as a number, giving 1, 2, 3, 10, 20.
Not correct sort -u
Wrong. -u suppresses duplicate lines in the output. The ordering stays the default lexical one.
Not correct sort -r
Wrong. -r only reverses the sort order; on lexical input it gives 3, 20, 2, 10, 1.
Why
By default sort compares lines as text, so "10" sorts before "2" because "1" precedes "2" character by character. -n is numeric, -r reverses, -u removes duplicates, -f folds case, and -k selects the field to compare on. These combine, so `sort -nr` is the usual descending numeric sort. GNU sort also has -h, human-numeric sort, which understands SI suffixes such as 2K, 512M, 1G — it would order plain integers correctly too, but -n is the option meant for them.
Where this comes from
- Cited
- LPI exam objective 103.2
- What it says
- Sort text streams, including numeric and reverse ordering.
Practise this
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